{"id":23620,"date":"2012-11-28T15:46:53","date_gmt":"2012-11-28T12:46:53","guid":{"rendered":"http:\/\/studentpmr.ru\/?p=23620"},"modified":"2012-11-28T15:46:53","modified_gmt":"2012-11-28T12:46:53","slug":"%d0%bb%d0%b8%d0%bd%d0%b5%d0%b9%d0%bd%d1%8b%d0%b5-%d0%b0%d0%bb%d0%b3%d0%be%d1%80%d0%b8%d1%82%d0%bc%d1%8b-%d0%bf%d1%80%d0%b8%d0%bc%d0%b5%d1%80%d1%8b-%d0%bf%d1%80%d0%be%d0%b3%d1%80%d0%b0%d0%bc%d0%bc-2","status":"publish","type":"post","link":"https:\/\/studentpmr.ru\/?p=23620","title":{"rendered":"\u041b\u0438\u043d\u0435\u0439\u043d\u044b\u0435 \u0430\u043b\u0433\u043e\u0440\u0438\u0442\u043c\u044b — \u043f\u0440\u0438\u043c\u0435\u0440\u044b \u043f\u0440\u043e\u0433\u0440\u0430\u043c\u043c. \u0427\u0430\u0441\u0442\u044c 2."},"content":{"rendered":"

\/\/elektronnye chasy pokazyvayut m chasov, n minut, k sekund
\n\/\/kakoe vremya oni pokazhut cherez p chasov, d minut, r sekund
\n\/\/ (0<=m<=23) (0<=n<=59) (0<=k<=59)\n#include
\n#include
\nvoid main()
\n{
\n clrscr();
\n unsigned m,n,k,p,d,r,ish,pr,kon;
\n printf(«Vvedite tekuschee pokazanie chasov (hh mm ss): «);
\n scanf(«%u%u%u»,&m,&n,&k);
\n printf(«Vvedite promezhutok vremeni (hh mm ss): «);
\n scanf(«%u%u%u»,&p,&d,&r);
\n ish=3600*m+60*n+k;
\n pr=3600*p+60*d+r;
\n kon=ish+pr;
\n m=kon\/3600;
\n kon-=m*3600;
\n n=kon\/60;
\n kon-=n*60;
\n k=kon;
\n printf(«Chasy pokazhut %u:%u:%u»,m,n,k);
\n getch();
\n}
\n<\/p>\n

\/\/opredeliv poryadkovyj nomer vved`nnogo simvola,
\n\/\/vyvesti preyduschij i posleduyuschij simvoly <\/p>\n

#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n unsigned char ch;
\n cprintf(«Vvedite lyuboj simvol: «);
\n ch=getche();
\n cprintf(«\\r\\nPoryadkovyj nomer: %u»,ch);
\n cprintf(«\\r\\nPredyduschij simvol — %c, posleduyuschij — %c»,ch-1,ch+1);
\n getch();
\n}<\/p>\n

\/\/perevesti ob’`m informatsii v bajtah v bolee krupnye edinitsy<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n printf(«Vvedite ob’`m informatsii v bajtah: «);
\n unsigned long a,k,m,g,t;
\n scanf(«%u»,&a);
\n k=a\/1024.0; \/\/kilobajty
\n m=k\/1024.0; \/\/megabajty
\n g=m\/1024.0; \/\/gigabajty
\n t=g\/1024.0; \/\/terabajty
\n printf(«Eto %f kilobajt, %f megabajt,\\n%f gigabajt, %f terabajt»,k,m,g,t);
\n getch();
\n}<\/p>\n

\/\/organizatsiej priobreteno n printerov i m komp’yuterov
\n\/\/vychislit’ stoimost’ vsej pokupki (vs` neobhodimoe vvesti s klaviatury)<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n unsigned n,m;
\n float p,k;
\n printf(«Skol’ko bylo kupleno printerov i komp’yuterov?\\n»);
\n scanf(«%u%u»,&n,&m);
\n printf(«Vvedite stoimost’ printera i stoimost’ komp’yutera: «);
\n scanf(«%f%f»,&p,&k);
\n printf(«Stoimost’ vsej pokupki %.2f rub.»,n*p+m*k);
\n getch();
\n}<\/p>\n

\/\/ugol A zadan v gradusah minutah i sekundah
\n\/\/najti ego velichinu v radianah<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n int deg;
\n unsigned min,sec;
\n printf(«Vvedite gradusy, minuty i sekundy (cherez probel): «);
\n scanf(«%i%u%u»,&deg,&min,&sec);
\n printf(«Eto %f radian»,3.1415923565*(deg+min*100\/60+sec*100\/60)\/180);
\n getch();
\n}<\/p>\n

\/\/perevesti v gradusy ugol, zadannyj v radianah<\/p>\n

#include
\n#include <\/p>\n

void main(void)<\/p>\n

{
\n clrscr();
\n printf(«Vvedite ugol v radianah: «);
\n float rad;
\n scanf(«%f»,&rad);
\n printf(«Eto %.3f gradusov»,rad*180\/3.14159265358979323);
\n getch();
\n}<\/p>\n

\/\/perevesti v metricheskuyu sistemu dlinu otrezka, zadannuyu v dyujmah<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n float inches,m,sm,mm;
\n printf(«Vvedite dlinu otrezka v dyujmah: «);
\n scanf(«%f»,&inches);
\n mm=inches*2.54;
\n sm=mm*10;
\n m=sm*100;
\n printf(«V metricheskoj sisteme: %.1f m, %.1f sm, %.1f mm»,m,sm,mm);
\n getch();
\n}<\/p>\n

\/\/vychislit’ prodolzhitel’nost’ promezhutka vremeni,
\n\/\/zadanogo svoimi nachalom i kontsom (v predelah odnih sutok)<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n printf(«\\tVychislenie dlitel’nosti promezhutka vremeni (v predelah odnih sutok)\\n»);
\n unsigned hour1,hour2,min1,min2,sek1,sek2,hour,min,sek,duration;
\n printf(«Vvedite moment nachala promezhutka (hh mm ss): «);
\n scanf(«%u%u%u»,&hour1,&min1,&sek1);
\n printf(«Vvedite moment kontsa promezhutka (hh mm ss): «);
\n scanf(«%u%u%u»,&hour2,&min2,&sek2);
\n duration=3600*(hour2-hour1)+60*(min2-min1)+sek2-sek1;
\n hour=duration\/3600;
\n duration-=3600*hour;
\n min=duration\/60;
\n duration-=60*min;
\n sek=duration;
\n printf(«Dlitel’nost’ etogo promezhourutka %2u chourasov, %2u minut, %2u sekund»,hour,min,sek);
\n getch();
\n}<\/p>\n

\/\/startovyj kapital K ezhemesyachno uvelichivaetsya na P%
\n\/\/cherez skol’ko let budet nakoplena summa S?<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n float k,p,s,n;
\n printf(«Vvedite razmer startovogo kapitala: «);
\n scanf(«%f»,&k);
\n printf(«Na skol’ko procentov uvelichivaetsya summa? «);
\n scanf(«%f»,&p);
\n printf(«Skol’ko trebuetsya nakopit’? «);
\n scanf(«%f»,&s);
\n n=s\/(k*p\/100);
\n printf(«Neobhodimaya summa budet nakoplena cherez %.2 let»,n);
\n getch();
\n}<\/p>\n

\/\/snachala bylo K kg semyan, odin kg kotoryh da`t P kg urozhaya
\n\/\/cherez skol’ko let mozhno budet zaseyat’ pole ploschad’yu S gektar<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n float k,p,n,s;
\n printf(«Skol’ko kg semyan bylo snahala? «);
\n scanf(«%f»,&k);
\n printf(«Kakova norma vysevki? «);
\n scanf(«%f»,&n);
\n printf(«Skol’ko kg semyan da`t odin poseyannyj kg? «);
\n scanf(«%f»,&p);
\n printf(«Kakoe pole nuzhno zaseyat’? «);
\n scanf(«%f»,&s);
\n printf(«Neobhodimyj urozhaj budet sobran cherez %.2f let»,k*p\/s);
\n getch();
\n}<\/p>\n

\/\/za pervyj god proizvoditel’nost’ na predpriyatii vyrosla na p1%,
\n\/\/za vtoroj — na p2% i za treitj — na p3%
\n\/\/najti srednegodovoj prirost proizvoditel’nosti<\/p>\n

#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n float p,p1,p2,p3;
\n printf(«Vvedite prirosty proizvoditel’nosti (v protsentah) za vse tri goda:»);
\n scanf(«%f%f%f»,&p1,&p2,&p3);
\n p=((1+p1*0.01)*(1+p2*0.01)*(1+p3*0.01))*100;
\n printf(«Srednegodovyj prirost raven %f protsentov»,p);
\n getch();
\n}<\/p>\n

\/\/najti korni kvadratnogo uravneniya, zadannogo svoimi koeffitsientami<\/p>\n

#include
\n#include
\n#include <\/p>\n

void main(void)<\/p>\n

{
\n clrscr();
\n printf(«\\tReshenie kvadratnogo uravneniya\\n»);
\n printf(«Vvedite coefficienty:\\n»);
\n float a,b,c,x1,x2;
\n printf(» a=»);
\n scanf(«%f»,&a);
\n printf(» b=»);
\n scanf(«%f»,&b);
\n printf(» c=»);
\n scanf(«%f»,&c);
\n x1=(-b-sqrt(d))\/(2*a);
\n x2=(-b+sqrt(d))\/(2*a);
\n printf(«Korni ravny %.3f i %.3f»,x1,x2);
\n printf(«Podstanovka: ax2+bx+c==%.4f»,a*x*x+b*x+c);
\n getch();
\n}<\/p>\n

\/\/preobrazovat’ kompleksnoe chislo v trigonometricheskuyu formu<\/p>\n

#include
\n#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n float x,y,r,f;
\n const k=180\/3.1415923565;
\n printf(«\\tKompleksnoe chislo z=x+iy\\nVVedite dejstvitel’nuyu i mnimuyu chast’: «);
\n scanf(«%f%f»,&x,&y);
\n r=sqrt(x*x+y*y);
\n f=atan(y\/x);
\n printf(«V trigonometricheskoj forme: z=%.3f*(%.3f+i*%.3f)»,r,cos(f)*k,sin(f)*k);
\n getch();
\n}<\/p>\n

\/\/najti ugol mezdhu peresekayuschimisya pryamymi<\/p>\n

#include
\n#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n printf(«\\tUgol mezhdu dvumya pryamymi na ploskosti\\nVvedite uglovye koefficienty dvuh pryamyh:»);
\n float k1,k2,b1,b2,angle;
\n printf(«y1=k1*x+b1 : «);
\n scanf(«%f%f»,&k1,&b1);
\n printf(«y2=k2*x+b2 : «);
\n scanf(«%f%f»,&k2,&b2);
\n angle=atan((k1-k2)\/(1-k1*k2))*180\/3.1415923565;
\n printf(«Ugol mezhdu etimi pryamymi raven %.3f»,anlge);
\n getch();
\n}<\/p>\n

\/\/najti ugol mezdhu peresekayuschimisya pryamymi<\/p>\n

#include
\n#include
\n#include <\/p>\n

void main()<\/p>\n

{
\n clrscr();
\n printf(«\\tUgol mezhdu dvumya pryamymi na ploskosti\\nVvedite uglovye koefficienty dvuh pryamyh:»);
\n float k1,k2,b1,b2,angle;
\n printf(«y1=k1*x+b1 : «);
\n scanf(«%f%f»,&k1,&b1);
\n printf(«y2=k2*x+b2 : «);
\n scanf(«%f%f»,&k2,&b2);
\n angle=atan((k1-k2)\/(1-k1*k2))*180\/3.1415923565;
\n printf(«Ugol mezhdu etimi pryamymi raven %.3f»,anlge);
\n getch();
\n}<\/p>\n","protected":false},"excerpt":{"rendered":"

\/\/elektronnye chasy pokazyvayut m chasov, n minut, k sekund \/\/kakoe vremya oni pokazhut cherez p chasov, d minut, r sekund \/\/ (0<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[36],"tags":[],"_links":{"self":[{"href":"https:\/\/studentpmr.ru\/index.php?rest_route=\/wp\/v2\/posts\/23620"}],"collection":[{"href":"https:\/\/studentpmr.ru\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/studentpmr.ru\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/studentpmr.ru\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/studentpmr.ru\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=23620"}],"version-history":[{"count":1,"href":"https:\/\/studentpmr.ru\/index.php?rest_route=\/wp\/v2\/posts\/23620\/revisions"}],"predecessor-version":[{"id":23621,"href":"https:\/\/studentpmr.ru\/index.php?rest_route=\/wp\/v2\/posts\/23620\/revisions\/23621"}],"wp:attachment":[{"href":"https:\/\/studentpmr.ru\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=23620"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/studentpmr.ru\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=23620"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/studentpmr.ru\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=23620"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}